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factorial - Why does 0! = 1? - Mathematics Stack Exchange

$\begingroup$ The theorem that $\binom{n}{k} = \frac{n!}{k!(n-k)!}$ already assumes $0!$ is defined to be $1$. Otherwise this would be restricted to $0 <k < n$. A reason that we do define $0!$ to be $1$ is so that we can cover those edge cases with the same formula, instead of having to treat them separately.

c++ - What does '\0' mean? - Stack Overflow

The \0 is treated as NULL Character. It is used to mark the end of the string in C. In C, string is a pointer pointing to array of characters with \0 at the end. So following will be valid representation of strings in C. char *c =”Hello”; // it is actually Hello\0 char c[] = {‘Y’,’o’,’\0′};

windows - Can't access 127.0.0.1 - Stack Overflow

Dec 31, 2015 · Good question. Just checked redis and it does work on 127.0.0.1. I guess it's because it doesn't use http, but it's special protocol RESP. Will update the question now. To the second part, this is not browser issue, Fiddler (for IIS) and Visual Studio Server Explorer (for azure emulator) both can't connect to 127.0.0.1. –

What is the difference between NULL, '\\0' and 0?

NULL is not guaranteed to be 0 -- its exact value is architecture-dependent. Most major architectures define it to (void*)0. '\0' will always equal 0, because that is how byte 0 is encoded in a character literal. I don't remember whether C compilers are required to use ASCII -- if not, '0' might not always equal 48.

What is %0|%0 and how does it work? - Stack Overflow

Nov 18, 2012 · @Pavel: What a .bat file does is: read instruction, at the end of file terminate. If you run %0: Process 1: starts, run %0 (thus create process 2); then die Process 2: starts, run %0 (thus create process 3); then die [...] you alway have at most 2 …

JSONDecodeError: Expecting value: line 1 column 1 (char 0)

json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)... During handling of the above exception, another exception occurred: requests.exceptions.JSONDecodeError: [Errno Expecting value] : 0. Therefore, when performing HEAD requests, make sure that there is a body in the response (which normally there isn't), before calling r ...

metadata file.dll couldnot be found - Stack Overflow

Jan 12, 2025 · How does this standard input operator (0<) work in Linux? In the standalone environment, how can I display a figure( including two tikzpictures) fully on a single page? What rule of Canadian law would allow for revocation of dual-citizenship status and passport because of national interest/disloyalty etc.?

What do $? $0 $1 $2 mean in shell script? - Stack Overflow

Mar 25, 2015 · A positional parameter is a parameter denoted by one or more digits, other than the single digit 0. Positional parameters are assigned from the shell’s arguments when it is invoked, and may be reassigned using the set builtin command.

`Invoke-Conda` cannot catch any arguments after powershell …

Jan 26, 2025 · I upgraded my powershell from 7.4.6 to 7.5.0. Then I found that I could not activate any conda environments and conda cannot catch any parameters: base 3.12.8 conda --version usage: conda-script...

c - What do 0LL or 0x0UL mean? - Stack Overflow

Aug 12, 2011 · LL designates a literal as a long long and UL designates one as unsigned long and 0x0 is hexadecimal for 0. So 0LL and 0x0UL are an equivalent number but different datatypes; the former is a long long and the latter is an unsigned long. There are many of these specifiers: 1F // float 1L // long 1ull // unsigned long long 1.0 // double