- Source: 1824 United States presidential election in Ohio
The 1824 United States presidential election in Ohio took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the presidency. Ohio voted for Henry Clay over Andrew Jackson, John Quincy Adams, and William H. Crawford. Clay won Ohio by a narrow margin of 1.53%. This was the first time that Ohio voted for a losing presidential candidate.
Results
See also
United States presidential elections in Ohio
References
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- Amerika Serikat
- Pemilihan umum Presiden Amerika Serikat 2016
- Ann Arbor, Michigan
- 1824 United States presidential election in Ohio
- 1824 United States presidential election
- United States presidential elections in Ohio
- 2024 United States presidential election in Ohio
- 2020 United States presidential election in Ohio
- 2004 United States presidential election in Ohio
- 2012 United States presidential election in Ohio
- 2016 United States presidential election in Ohio
- 1988 United States presidential election in Ohio
- 1996 United States presidential election in Ohio