- Source: 1836 United States presidential election in Pennsylvania
The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%. The result would ultimately prove decisive in Van Buren's victory; had Harrison won the state, then Van Buren would not have achieved a majority in the Electoral College, meaning that the election would have been decided in the House of Representatives.
Results
See also
List of United States presidential elections in Pennsylvania
References
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- Presiden Amerika Serikat
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- 1836 United States presidential election in Pennsylvania
- 1836 United States presidential election
- 2024 United States presidential election in Pennsylvania
- 2020 United States presidential election in Pennsylvania
- United States presidential elections in Pennsylvania
- 2016 United States presidential election in Pennsylvania
- 1984 United States presidential election in Pennsylvania
- 1992 United States presidential election in Pennsylvania
- 2000 United States presidential election in Pennsylvania
- 2024 United States presidential election in Michigan