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Source: 1860 United States presidential election in Missouri

The 1860 United States presidential election in Missouri took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.
Missouri was won by Democratic candidate Stephen A. Douglas, by a very narrow margin of 0.26%. The state was the only one to fully give its votes to Douglas, though he won the popular vote and three of the seven electoral votes from New Jersey under a fusion ticket.
As of the 2020 presidential election, this is the last occasion when Putnam County, Ozark County, and Taney County voted for a candidate running as a Democrat, with the former voting for Douglas and the latter two voting for Breckinridge. This was also the last election until 1984 in which Monroe County did not vote for the Democratic candidate. This was the first time in American history that four candidates each won at least one county in the same state, something that has only been repeated in 1912 (in North Dakota and in Kansas).

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