- Source: 1890 United States gubernatorial elections
United States gubernatorial elections were held in 1890, in 27 states, concurrent with the House and Senate elections, on November 4, 1890 (except in Alabama, Arkansas, Georgia, Idaho, Maine, Oregon, Rhode Island, Vermont and Wyoming, which held early elections).
In New Hampshire, the newly elected Governor's term began in the January following the election for the first time, rather than in the following June as previously.
Idaho and Wyoming held their first gubernatorial elections on achieving statehood.
Results
See also
1890 United States elections
References
Notes
Bibliography
Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
Dubin, Michael J. (2014). United States Gubernatorial Elections, 1861-1911: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-4722-0.
The World Almanac and Bureau of Information, 1891. New York, NY: The Press Publishing Co. 1891.
McPherson, Edward, ed. (1891). The Tribune Almanac and Political Register for 1891. New York, NY: The Tribune Association.
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- 1890 United States gubernatorial elections
- 1890 United States elections
- 1890 United States House of Representatives elections
- 1890 Minnesota gubernatorial election
- 1890 Georgia gubernatorial election
- 1890 Nebraska gubernatorial election
- 1890 Texas gubernatorial election
- 1890 Alabama gubernatorial election
- 1890 Maine gubernatorial election
- 1890 Colorado gubernatorial election
