- Source: Elongated triangular pyramid
In geometry, the elongated triangular pyramid is one of the Johnson solids (J7). As the name suggests, it can be constructed by elongating a tetrahedron by attaching a triangular prism to its base. Like any elongated pyramid, the resulting solid is topologically (but not geometrically) self-dual.
Construction
The elongated triangular pyramid is constructed from a triangular prism by attaching regular tetrahedron onto one of its bases, a process known as elongation. The tetrahedron covers an equilateral triangle, replacing it with three other equilateral triangles, so that the resulting polyhedron has four equilateral triangles and three squares as its faces. A convex polyhedron in which all of the faces are regular polygons is called the Johnson solid, and the elongated triangular pyramid is among them, enumerated as the seventh Johnson solid
J
7
{\displaystyle J_{7}}
.
Properties
An elongated triangular pyramid with edge length
a
{\displaystyle a}
has a height, by adding the height of a regular tetrahedron and a triangular prism:
(
1
+
6
3
)
a
≈
1.816
a
.
{\displaystyle \left(1+{\frac {\sqrt {6}}{3}}\right)a\approx 1.816a.}
Its surface area can be calculated by adding the area of all eight equilateral triangles and three squares:
(
3
+
3
)
a
2
≈
4.732
a
2
,
{\displaystyle \left(3+{\sqrt {3}}\right)a^{2}\approx 4.732a^{2},}
and its volume can be calculated by slicing it into a regular tetrahedron and a prism, adding their volume up::
(
1
12
(
2
+
3
3
)
)
a
3
≈
0.551
a
3
.
{\displaystyle \left({\frac {1}{12}}\left({\sqrt {2}}+3{\sqrt {3}}\right)\right)a^{3}\approx 0.551a^{3}.}
It has the three-dimensional symmetry group, the cyclic group
C
3
v
{\displaystyle C_{3\mathrm {v} }}
of order 6. Its dihedral angle can be calculated by adding the angle of the tetrahedron and the triangular prism:
the dihedral angle of a tetrahedron between two adjacent triangular faces is
arccos
(
1
3
)
≈
70.5
∘
{\textstyle \arccos \left({\frac {1}{3}}\right)\approx 70.5^{\circ }}
;
the dihedral angle of the triangular prism between the square to its bases is
π
2
=
90
∘
{\textstyle {\frac {\pi }{2}}=90^{\circ }}
, and the dihedral angle between square-to-triangle, on the edge where tetrahedron and triangular prism are attached, is
arccos
(
1
3
)
+
π
2
≈
160.5
∘
{\textstyle \arccos \left({\frac {1}{3}}\right)+{\frac {\pi }{2}}\approx 160.5^{\circ }}
;
the dihedral angle of the triangular prism between two adjacent square faces is the internal angle of an equilateral triangle
π
3
=
60
∘
{\textstyle {\frac {\pi }{3}}=60^{\circ }}
.
References
External links
Weisstein, Eric W., "Johnson solid" ("Elongated triangular pyramid") at MathWorld.
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