• Source: Sums of three cubes
    • In the mathematics of sums of powers, it is an open problem to characterize the numbers that can be expressed as a sum of three cubes of integers, allowing both positive and negative cubes in the sum. A necessary condition for an integer



      n


      {\displaystyle n}

      to equal such a sum is that



      n


      {\displaystyle n}

      cannot equal 4 or 5 modulo 9, because the cubes modulo 9 are 0, 1, and −1, and no three of these numbers can sum to 4 or 5 modulo 9. It is unknown whether this necessary condition is sufficient.
      Variations of the problem include sums of non-negative cubes and sums of rational cubes. All integers have a representation as a sum of rational cubes, but it is unknown whether the sums of non-negative cubes form a set with non-zero natural density.


      Small cases


      A nontrivial representation of 0 as a sum of three cubes would give a counterexample to Fermat's Last Theorem for the exponent three, as one of the three cubes would have the opposite sign as the other two and its negation would equal the sum of the other two. Therefore, by Leonhard Euler's proof of that case of Fermat's last theorem, there are only the trivial solutions





      a

      3


      +
      (

      a

      )

      3


      +

      0

      3


      =
      0.


      {\displaystyle a^{3}+(-a)^{3}+0^{3}=0.}


      For representations of 1 and 2, there are infinite families of solutions




      (
      9

      b

      4



      )

      3


      +
      (
      3
      b

      9

      b

      4



      )

      3


      +
      (
      1

      9

      b

      3



      )

      3


      =
      1


      {\displaystyle (9b^{4})^{3}+(3b-9b^{4})^{3}+(1-9b^{3})^{3}=1}

      (discovered by K. Mahler in 1936)
      and




      (
      1
      +
      6

      c

      3



      )

      3


      +
      (
      1

      6

      c

      3



      )

      3


      +
      (

      6

      c

      2



      )

      3


      =
      2


      {\displaystyle (1+6c^{3})^{3}+(1-6c^{3})^{3}+(-6c^{2})^{3}=2}

      (discovered by A.S. Verebrusov in 1908, quoted by L.J. Mordell).
      These can be scaled to obtain representations for any cube or any number that is twice a cube. There are also other known representations of 2 that are not given by these infinite families:




      1

      214


      928

      3


      +
      3

      480


      205

      3


      +
      (

      3

      528

      875

      )

      3


      =
      2
      ,


      {\displaystyle 1\ 214\ 928^{3}+3\ 480\ 205^{3}+(-3\ 528\ 875)^{3}=2,}





      37

      404

      275


      617

      3


      +
      (

      25

      282

      289

      375

      )

      3


      +
      (

      33

      071

      554

      596

      )

      3


      =
      2
      ,


      {\displaystyle 37\ 404\ 275\ 617^{3}+(-25\ 282\ 289\ 375)^{3}+(-33\ 071\ 554\ 596)^{3}=2,}





      3

      737

      830

      626


      090

      3


      +
      1

      490

      220

      318


      001

      3


      +
      (

      3

      815

      176

      160

      999

      )

      3


      =
      2.


      {\displaystyle 3\ 737\ 830\ 626\ 090^{3}+1\ 490\ 220\ 318\ 001^{3}+(-3\ 815\ 176\ 160\ 999)^{3}=2.}


      However, 1 and 2 are the only numbers with representations that can be parameterized by quartic polynomials as above.
      Even in the case of representations of 3, Louis J. Mordell wrote in 1953 "I do not know anything" more than its small solutions





      1

      3


      +

      1

      3


      +

      1

      3


      =

      4

      3


      +

      4

      3


      +
      (

      5

      )

      3


      =
      3


      {\displaystyle 1^{3}+1^{3}+1^{3}=4^{3}+4^{3}+(-5)^{3}=3}


      and the fact that each of the three cubed numbers must be equal modulo 9.


      Computational results


      Since 1955, and starting with the instigation of Mordell, many authors have implemented computational searches for these representations.
      Elsenhans & Jahnel (2009) used a method of Noam Elkies (2000) involving lattice reduction to search for all solutions to the Diophantine equation





      x

      3


      +

      y

      3


      +

      z

      3


      =
      n


      {\displaystyle x^{3}+y^{3}+z^{3}=n}


      for positive



      n


      {\displaystyle n}

      at most 1000 and for



      max
      (

      |

      x

      |

      ,

      |

      y

      |

      ,

      |

      z

      |

      )
      <

      10

      14




      {\displaystyle \max(|x|,|y|,|z|)<10^{14}}

      , leaving only 33, 42, 74, 114, 165, 390, 579, 627, 633, 732, 795, 906, 921, and 975 as open problems in 2009 for



      n

      1000


      {\displaystyle n\leq 1000}

      , and 192, 375, and 600 remain with no primitive solutions (i.e.



      gcd
      (
      x
      ,
      y
      ,
      z
      )
      =
      1


      {\displaystyle \gcd(x,y,z)=1}

      ). After Timothy Browning covered the problem on Numberphile in 2016, Huisman (2016) extended these searches to



      max
      (

      |

      x

      |

      ,

      |

      y

      |

      ,

      |

      z

      |

      )
      <

      10

      15




      {\displaystyle \max(|x|,|y|,|z|)<10^{15}}

      solving the case of 74, with solution




      74
      =
      (

      284

      650

      292

      555

      885

      )

      3


      +
      66

      229

      832

      190


      556

      3


      +
      283

      450

      105

      697


      727

      3


      .


      {\displaystyle 74=(-284\ 650\ 292\ 555\ 885)^{3}+66\ 229\ 832\ 190\ 556^{3}+283\ 450\ 105\ 697\ 727^{3}.}


      Through these searches, it was discovered that all



      n
      <
      100


      {\displaystyle n<100}

      that are unequal to 4 or 5 modulo 9 have a solution, with at most two exceptions, 33 and 42.
      However, in 2019, Andrew Booker settled the case



      n
      =
      33


      {\displaystyle n=33}

      by discovering that




      33
      =
      8

      866

      128

      975

      287


      528

      3


      +
      (

      8

      778

      405

      442

      862

      239

      )

      3


      +
      (

      2

      736

      111

      468

      807

      040

      )

      3


      .


      {\displaystyle 33=8\ 866\ 128\ 975\ 287\ 528^{3}+(-8\ 778\ 405\ 442\ 862\ 239)^{3}+(-2\ 736\ 111\ 468\ 807\ 040)^{3}.}


      In order to achieve this, Booker exploited an alternative search strategy with running time proportional to



      min
      (

      |

      x

      |

      ,

      |

      y

      |

      ,

      |

      z

      |

      )


      {\displaystyle \min(|x|,|y|,|z|)}

      rather than to their maximum, an approach originally suggested by Heath-Brown et al. He also found that




      795
      =
      (

      14

      219

      049

      725

      358

      227

      )

      3


      +
      14

      197

      965

      759

      741


      571

      3


      +
      2

      337

      348

      783

      323


      923

      3


      ,


      {\displaystyle 795=(-14\ 219\ 049\ 725\ 358\ 227)^{3}+14\ 197\ 965\ 759\ 741\ 571^{3}+2\ 337\ 348\ 783\ 323\ 923^{3},}


      and established that there are no solutions for



      n
      =
      42


      {\displaystyle n=42}

      or any of the other unresolved



      n

      1000


      {\displaystyle n\leq 1000}

      with




      |

      z

      |



      10

      16




      {\displaystyle |z|\leq 10^{16}}

      .
      Shortly thereafter, in September 2019, Booker and Andrew Sutherland finally settled the



      n
      =
      42


      {\displaystyle n=42}

      case, using 1.3 million hours of computing on the Charity Engine global grid to discover that




      42
      =
      (

      80

      538

      738

      812

      075

      974

      )

      3


      +
      80

      435

      758

      145

      817


      515

      3


      +
      12

      602

      123

      297

      335


      631

      3


      ,


      {\displaystyle 42=(-80\ 538\ 738\ 812\ 075\ 974)^{3}+80\ 435\ 758\ 145\ 817\ 515^{3}+12\ 602\ 123\ 297\ 335\ 631^{3},}


      as well as solutions for several other previously unknown cases including



      n
      =
      165


      {\displaystyle n=165}

      and



      579


      {\displaystyle 579}

      for



      n

      1000


      {\displaystyle n\leq 1000}

      .
      Booker and Sutherland also found a third representation of 3 using a further 4 million computer-hours on Charity Engine:




      3
      =
      569

      936

      821

      221

      962

      380


      720

      3


      +
      (

      569

      936

      821

      113

      563

      493

      509

      )

      3


      +
      (

      472

      715

      493

      453

      327

      032

      )

      3


      .


      {\displaystyle 3=569\ 936\ 821\ 221\ 962\ 380\ 720^{3}+(-569\ 936\ 821\ 113\ 563\ 493\ 509)^{3}+(-472\ 715\ 493\ 453\ 327\ 032)^{3}.}


      This discovery settled a 65-year-old question of Louis J. Mordell that has stimulated much of the research on this problem.
      While presenting the third representation of 3 during his appearance in a video on the Youtube channel Numberphile, Booker also presented a representation for 906:




      906
      =
      (

      74

      924

      259

      395

      610

      397

      )

      3


      +
      72

      054

      089

      679

      353


      378

      3


      +
      35

      961

      979

      615

      356


      503

      3


      .


      {\displaystyle 906=(-74\ 924\ 259\ 395\ 610\ 397)^{3}+72\ 054\ 089\ 679\ 353\ 378^{3}+35\ 961\ 979\ 615\ 356\ 503^{3}.}


      The only remaining unsolved cases up to 1,000 are the seven numbers 114, 390, 627, 633, 732, 921, and 975, and there are no known primitive solutions (i.e.



      gcd
      (
      x
      ,
      y
      ,
      z
      )
      =
      1


      {\displaystyle \gcd(x,y,z)=1}

      ) for 192, 375, and 600.


      Popular interest


      The sums of three cubes problem has been popularized in recent years by Brady Haran, creator of the YouTube channel Numberphile, beginning with the 2015 video "The Uncracked Problem with 33" featuring an interview with Timothy Browning. This was followed six months later by the video "74 is Cracked" with Browning, discussing Huisman's 2016 discovery of a solution for 74. In 2019, Numberphile published three related videos, "42 is the new 33", "The mystery of 42 is solved", and "3 as the sum of 3 cubes", to commemorate the discovery of solutions for 33, 42, and the new solution for 3.
      Booker's solution for 33 was featured in articles appearing in Quanta Magazine and New Scientist, as well as an article in Newsweek in which Booker's collaboration with Sutherland was announced: "...the mathematician is now working with Andrew Sutherland of MIT in an attempt to find the solution for the final unsolved number below a hundred: 42". The number 42 has additional popular interest due to its appearance in the 1979 Douglas Adams science fiction novel The Hitchhiker's Guide to the Galaxy as the answer to The Ultimate Question of Life, the Universe, and Everything.
      Booker and Sutherland's announcements of a solution for 42 received international press coverage, including articles in New Scientist, Scientific American, Popular Mechanics, The Register, Die Zeit, Der Tagesspiegel, Helsingin Sanomat, Der Spiegel, New Zealand Herald, Indian Express, Der Standard, Las Provincias, Nettavisen, Digi24, and BBC World Service. Popular Mechanics named the solution for 42 as one of the "10 Biggest Math Breakthroughs of 2019".
      The resolution of Mordell's question by Booker and Sutherland a few weeks later sparked another round of news coverage.
      In Booker's invited talk at the fourteenth Algorithmic Number Theory Symposium he discusses some of the popular interest in this problem and the public reaction to the announcement of solutions for 33 and 42.


      Solvability and decidability


      In 1992, Roger Heath-Brown conjectured that every



      n


      {\displaystyle n}

      unequal to 4 or 5 modulo 9 has infinitely many representations as sums of three cubes.
      The case



      n
      =
      33


      {\displaystyle n=33}

      of this problem was used by Bjorn Poonen as the opening example in a survey on undecidable problems in number theory, of which Hilbert's tenth problem is the most famous example. Although this particular case has since been resolved, it is unknown whether representing numbers as sums of cubes is decidable. That is, it is not known whether an algorithm can, for every input, test in finite time whether a given number has such a representation.
      If Heath-Brown's conjecture is true, the problem is decidable. In this case, an algorithm could correctly solve the problem by computing



      n


      {\displaystyle n}

      modulo 9, returning false when this is 4 or 5, and otherwise returning true. Heath-Brown's research also includes more precise conjectures on how far an algorithm would have to search to find an explicit representation rather than merely determining whether one exists.


      Variations


      A variant of this problem related to Waring's problem asks for representations as sums of three cubes of non-negative integers. In the 19th century, Carl Gustav Jacob Jacobi and collaborators compiled tables of solutions to this problem. It is conjectured that the representable numbers have positive natural density. This remains unknown, but Trevor Wooley has shown that



      Ω
      (

      n

      0.917


      )


      {\displaystyle \Omega (n^{0.917})}

      of the numbers from



      1


      {\displaystyle 1}

      to



      n


      {\displaystyle n}

      have such representations. The density is at most



      Γ
      (
      4

      /

      3

      )

      3



      /

      6

      0.119


      {\displaystyle \Gamma (4/3)^{3}/6\approx 0.119}

      .
      Every integer can be represented as a sum of three cubes of rational numbers (rather than as a sum of cubes of integers).


      See also


      Sum of four cubes problem, whether every integer is a sum of four cubes
      Euler's sum of powers conjecture § k = 3, relating to cubes that can be written as a sum of three positive cubes
      Plato's number, an ancient text possibly discussing the equation 33 + 43 + 53 = 63
      Taxicab number, the smallest integer that can be expressed as a sum of two positive integer cubes in n distinct ways


      References




      External links


      Solutions of n = x3 + y3 + z3 for 0 ≤ n ≤ 99, Hisanori Mishima
      threecubes, Daniel J. Bernstein
      Sums of three cubes, Mathpages

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