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Angular diameter GudangMovies21 Rebahinxxi LK21
The angular diameter, angular size, apparent diameter, or apparent size is an angular separation (in units of angle) describing how large a sphere or circle appears from a given point of view. In the vision sciences, it is called the visual angle, and in optics, it is the angular aperture (of a lens). The angular diameter can alternatively be thought of as the angular displacement through which an eye or camera must rotate to look from one side of an apparent circle to the opposite side.
A person can resolve with their naked eyes diameters down to about 1 arcminute (approximately 0.017° or 0.0003 radians). This corresponds to 0.3 m at a 1 km distance, or to perceiving Venus as a disk under optimal conditions.
Formulation
The angular diameter of a circle whose plane is perpendicular to the displacement vector between the point of view and the center of said circle can be calculated using the formula
δ
=
2
arctan
(
d
2
D
)
,
{\displaystyle \delta =2\arctan \left({\frac {d}{2D}}\right),}
in which
δ
{\displaystyle \delta }
is the angular diameter (in units of angle, normally radians, sometimes in degrees, depending on the arctangent implementation),
d
{\displaystyle d}
is the linear diameter of the object (in units of length), and
D
{\displaystyle D}
is the distance to the object (also in units of length). When
D
≫
d
{\displaystyle D\gg d}
, we have:
δ
≈
d
/
D
{\displaystyle \delta \approx d/D}
,
and the result obtained is necessarily in radians.
= For a sphere
=For a spherical object whose linear diameter equals
d
{\displaystyle d}
and where
D
{\displaystyle D}
is the distance to the center of the sphere, the angular diameter can be found by the following modified formula
δ
=
2
arcsin
(
d
2
D
)
{\displaystyle \delta =2\arcsin \left({\frac {d}{2D}}\right)}
Such a different formulation is because the apparent edges of a sphere are its tangent points, which are closer to the observer than the center of the sphere, and have a distance between them which is smaller than the actual diameter. The above formula can be found by understanding that in the case of a spherical object, a right triangle can be constructed such that its three vertices are the observer, the center of the sphere, and one of the sphere's tangent points, with
D
{\displaystyle D}
as the hypotenuse and
d
a
c
t
2
D
{\displaystyle {\frac {d_{\mathrm {act} }}{2D}}}
as the sine.
The formula is related to the zenith angle to the horizon,
δ
=
π
−
2
arccos
(
R
R
+
h
)
{\displaystyle \delta =\pi -2\arccos \left({\frac {R}{R+h}}\right)}
where R is the radius of the sphere and h is the distance to the near surface of the sphere.
The difference with the case of a perpendicular circle is significant only for spherical objects of large angular diameter, since the following small-angle approximations hold for small values of
x
{\displaystyle x}
:
arcsin
x
≈
arctan
x
≈
x
.
{\displaystyle \arcsin x\approx \arctan x\approx x.}
Estimating angular diameter using the hand
Estimates of angular diameter may be obtained by holding the hand at right angles to a fully extended arm, as shown in the figure.
Use in astronomy
In astronomy, the sizes of celestial objects are often given in terms of their angular diameter as seen from Earth, rather than their actual sizes. Since these angular diameters are typically small, it is common to present them in arcseconds (″). An arcsecond is 1/3600th of one degree (1°) and a radian is 180/π degrees. So one radian equals 3,600 × 180/
π
{\displaystyle \pi }
arcseconds, which is about 206,265 arcseconds (1 rad ≈ 206,264.806247"). Therefore, the angular diameter of an object with physical diameter d at a distance D, expressed in arcseconds, is given by:
δ
=
206
,
265
(
d
/
D
)
a
r
c
s
e
c
o
n
d
s
{\displaystyle \delta =206,265~(d/D)~\mathrm {arcseconds} }
.
These objects have an angular diameter of 1″:
an object of diameter 1 cm at a distance of 2.06 km
an object of diameter 725.27 km at a distance of 1 astronomical unit (AU)
an object of diameter 45 866 916 km at 1 light-year
an object of diameter 1 AU (149 597 871 km) at a distance of 1 parsec (pc)
Thus, the angular diameter of Earth's orbit around the Sun as viewed from a distance of 1 pc is 2″, as 1 AU is the mean radius of Earth's orbit.
The angular diameter of the Sun, from a distance of one light-year, is 0.03″, and that of Earth 0.0003″. The angular diameter 0.03″ of the Sun given above is approximately the same as that of a human body at a distance of the diameter of Earth.
This table shows the angular sizes of noteworthy celestial bodies as seen from Earth:
The angular diameter of the Sun, as seen from Earth, is about 250,000 times that of Sirius. (Sirius has twice the diameter and its distance is 500,000 times as much; the Sun is 1010 times as bright, corresponding to an angular diameter ratio of 105, so Sirius is roughly 6 times as bright per unit solid angle.)
The angular diameter of the Sun is also about 250,000 times that of Alpha Centauri A (it has about the same diameter and the distance is 250,000 times as much; the Sun is 4×1010 times as bright, corresponding to an angular diameter ratio of 200,000, so Alpha Centauri A is a little brighter per unit solid angle).
The angular diameter of the Sun is about the same as that of the Moon. (The Sun's diameter is 400 times as large and its distance also; the Sun is 200,000 to 500,000 times as bright as the full Moon (figures vary), corresponding to an angular diameter ratio of 450 to 700, so a celestial body with a diameter of 2.5–4″ and the same brightness per unit solid angle would have the same brightness as the full Moon.)
Even though Pluto is physically larger than Ceres, when viewed from Earth (e.g., through the Hubble Space Telescope) Ceres has a much larger apparent size.
Angular sizes measured in degrees are useful for larger patches of sky. (For example, the three stars of the Belt cover about 4.5° of angular size.) However, much finer units are needed to measure the angular sizes of galaxies, nebulae, or other objects of the night sky.
Degrees, therefore, are subdivided as follows:
360 degrees (°) in a full circle
60 arc-minutes (′) in one degree
60 arc-seconds (″) in one arc-minute
To put this in perspective, the full Moon as viewed from Earth is about 1⁄2°, or 30′ (or 1800″). The Moon's motion across the sky can be measured in angular size: approximately 15° every hour, or 15″ per second. A one-mile-long line painted on the face of the Moon would appear from Earth to be about 1″ in length.
In astronomy, it is typically difficult to directly measure the distance to an object, yet the object may have a known physical size (perhaps it is similar to a closer object with known distance) and a measurable angular diameter. In that case, the angular diameter formula can be inverted to yield the angular diameter distance to distant objects as
d
≡
2
D
tan
(
δ
2
)
.
{\displaystyle d\equiv 2D\tan \left({\frac {\delta }{2}}\right).}
In non-Euclidean space, such as our expanding universe, the angular diameter distance is only one of several definitions of distance, so that there can be different "distances" to the same object. See Distance measures (cosmology).
= Non-circular objects
=Many deep-sky objects such as galaxies and nebulae appear non-circular and are thus typically given two measures of diameter: major axis and minor axis. For example, the Small Magellanic Cloud has a visual apparent diameter of 5° 20′ × 3° 5′.
= Defect of illumination
=Defect of illumination is the maximum angular width of the unilluminated part of a celestial body seen by a given observer. For example, if an object is 40″ of arc across and is 75% illuminated, the defect of illumination is 10″.
See also
Angular diameter distance
Angular resolution
Apparent magnitude
List of stars with resolved images
Moon illusion
Perceived visual angle
Solid angle
Visual acuity
Visual angle
References
External links
Small-Angle Formula (archived 7 October 1997)
Visual Aid to the Apparent Size of the Planets
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